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Step2247 [10]
3 years ago
7

John leaves school to go home.his bus drives 6 kilometers north and then goes 7 kilometers west.how far is John's house from the

school?
Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

John is 9.21 km form the school.

Step-by-step explanation:

John leaves school to go home. His bus drives 6 kilometres north and then goes 7 kilometres west. It is required to find John's distance from the school. It is equal to the shortest path covered or its displacement. So,

d=\sqrt{6^2+7^2} \\\\d=9.21\ km

So, John is 9.21 km form the school.

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Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

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Answer:

Show blocks as addends and the sum as a bigger block

Step-by-step explanation:

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Anastasy [175]

Answer:

3x4^3/34

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Describe how you could find the product of 700 and 900
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Prove that:<br><br>cos20°cos40°cos80°=1/8​
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Answer:

see explanation

Step-by-step explanation:

Using the double angle identity for sine

sin2x = 2sinxcosx

Consider left side

cos20°cos40°cos80°

= \frac{1}{2sin20} (2sin20°cos20°)cos40°cos80°

= \frac{1}{4sin20} (2sin40°cos40°)cos80°

= \frac{1}{4sin20} (sin80°cos80° )

= \frac{1}{8sin20} (2sin80°cos80° )

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= \frac{1}{8} = right side , thus proven

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