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Tems11 [23]
3 years ago
8

Which of the following groups in the Domain Archaea require high salt concentrations for survival?

Biology
1 answer:
dezoksy [38]3 years ago
4 0

The correct answer is: halophiles

Halophiles on Greek means "salt-loving", so organisms that belong to this group are extremophiles (survive in extreme environment) that live in high salt concentration. Halophiles usually belong to Archaea, but can be found in Bacteria domain and sometimes even Eukarya.

Halophiles can survive on very salty environments (with a concentration of salt that is five times greater than the salt concentration of the ocean.

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Which of the following statements is true?
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Earth's atmosphere helps maintain a constant temperature.

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Now, raise one of your hands just slightly and press both hands together again. This motion models a thick plate pressing agains
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Term referring to the process in which certain compounds increase in concentration within biotic tissues as they move up through
melisa1 [442]

Answer:

a. Biomagnification

Explanation:

Biomagnification is the name given to the progressive accumulation of substances from one trophic level to another along a food chain. Thus, the substance will have its highest concentration in individuals who occupy trophic levels furthest from producers.

For biomagnification to occur, substances must be fat soluble (lipid soluble) and thus adhere to living tissues. Another feature of substances that undergo biomagnification is that they are generally not biodegradable or metabolized by the body.

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3 0
3 years ago
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m
Vanyuwa [196]
This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

<span>Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
v=\frac{2\pi{r}}{T}
</span>=\frac{2\pi{r}}{1.88*365.25*86400} m/s, accounting for leap years
=3.371*10^{-8}\pi{r}   m/s

The centripetal force, Fc, generated is
Fc=\frac{mv^2}{r}   
        where m=mass of mars = 6.39*10^(24) kg
=\frac{mv^2}{r}
=\frac{6.39*10^{24}v^2}{r}
=7.26168*10^9\pi^2r

The gravitation pull from the sun, Fg, is given by
Fg=\frac{GMm}{r^2}
    where G=grav. const., =6.67408*10^(-11) m^3<span> kg^(</span>-1)<span> s^(</span>-2)
              M=mass of sun=1.989*10^(30) kg
=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}
=\frac{8.4826*10^44}{r^2}

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}
Solving for the real root:
r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}
=\frac{1.1681263*10^{35}}{\pi^2}
=2.279*10^11 m


5 0
3 years ago
Need help with 34 ASAP!!
Deffense [45]

Answer:

A.

Explanation:

It is A because the diagram for choice A shows correctly how cellular respiration produces energy and releases carbon dioxide and water as byproducts(CO2). And it also shows how photosynthesis release or produces oxygen gas (O2)

3 0
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