Answer:
∠2 = 150°, it is a supplementary angle to 30°
∠3 = 30°, it is an alternate angle to 30°
∠4 = 150°, it is a supplementary angle to 30°
∠5 = 30°, it is an alternate angle to 30°
∠6 = 150°, it is a supplementary angle to 30°
∠7 = 30°, it is an alternate angle to 30°
∠8 = 150°, it is a supplementary angle to 30°
2x-y=-8
+
y=2
2x=-6
x=-3
2*-3-y=-8
-6-y=-8
-y=-2
x=-3 and y=2
Answer:

Step-by-step explanation:
At the start of the day there are g pounds of gravel in the quarry.
Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.
Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.
Then it says that at this point, the amount of pounds in the mound are 1500. Hence we get

To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:

And so 
Answer:
C. 303,000 Joules
Step-by-step explanation:
1. use abcos(theta)
a=50
b=7000
theta=30 degrees
2. (50)(7000)cos(30)=303,000
The confidence interval for the mean usage of water is (18.7,20.5).
Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.
We have to find the confidence interval for the mean usage of water.
To find out the confidence interval we have to first find margin of error.
μ=19.5
σ=2.4
α=0.98
α/2=0.49
We have to find the z value for the p value 0.49 which is z=2.33
Margin of error=z*μ/
=2.33*19.5/
=0.82
lower level=mean -m
=19.5-0.82
=18.68
after rounding upto 1 decimal
=18.7
upper mean = mean+m
=19.5+0.82
=20.52
Hence the confidence interval for the usage of water is (18.7,20.52).
Learn more about margin of error at brainly.com/question/10218601
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