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ololo11 [35]
3 years ago
9

2.) I am a two-digit number that can be referred to as a perfect square. The sum of my two digits is 10. What number am I?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer: 64

Step-by-step explanation:

By definition, a perfect square is the square of a whole number.

The information given in the problem that you must keep on mind is:

- The number has two digits.

- The number is a perfect square ( Is obtained by squaring a whole number).

- The sum of its two digits is 10.

The number 64 is formed by the digit 6 and the digit 4. The sum of both digits is:

6+4=10

The number 64 can be written as:

64=8*8=8^2

Then, it is perfect square.

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Two trapezoids below are similar what is the length of RS?
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  11.5 m

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The coordinates of the vertices of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .
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Given coordinates of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .

and coordinates of the vertices of △R′S′T′ are R′(1, −2) , S′(1, 0) , and T′(5, −3) .

Solution : We know the rule for the new coordinates of rotatation 90°counterclockwise about the origin.The rule is (h, k) ---> (-k,h).

Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.

In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.

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R(−3, −1) --> R′(1, -3).

S(−1, −1) --> S′(1, -1).

T(−4, −5)  --> T′(5, −4).

Let us apply another rule, each of the y-coordinate is getting reduced by 1 by adding 1 to the new coordinates.

Adding 1 to y-coordinates, we get

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(5, −4) --> (5,-4+1) --> T' (5,-3).

So, the transformations steps would be:

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4 0
2 years ago
Read 2 more answers
Chen uses different strategies to add. He works with the addends 4,5,6,7
Lelu [443]
You can do 6 I guess. Then do 6+6=12
4 0
3 years ago
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