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3 years ago

Heeeellllllllllllllp!!!

Mathematics

1 answer:

tester [92]3 years ago

4 0

1⅓πr³ = 36π
r³ = 36π/1⅓π
r³ = 27
r = ³√27
r = 3 feet

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Omllllll please helpp

vagabundo [1.1K]

Answer:

a. 8x^3y^3

b. x^5

Step-by-step explanation:

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3 years ago

What is the measure of 143°<br> 61°<br> Enter the answer in the box.

Keith_Richards [23]

Answer:

angle CAB=37° angle ABC=82°

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3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago

Read 45 pages of her book in 2 hours .at that rate how many would she read in 12 hours?

8_murik_8 [283]

2 hours = 45 pages

1 hour = 45 ÷ 2 = 22.5 pages

12 hours = 22.5 x 12 = 270 pages

Answer; 270 pages

5 0

3 years ago

Please help i can not figure it out

Alisiya [41]

To solve this problem you need to figure out the volume of the sipping container, and the volume of the tissue box.
39*19.5*19.5=14,829.75
6.5*6.5*6.5=274.63

In order to figure out how many fits you need to divide
14,829.75/274.63=53.99

The maximum number that you can fit is the box is 53.

Hope this helps

4 0

3 years ago