Answer:
1/2 < 3/5 < 2/3 < 5/6 least to greatest
Step-by-step explanation:
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
Answer:
hieght at left is 24+1
and right is 25 both are equal now so h=25
base=8
area of triangle 1/2×b×h
1/2×8×25=100
An = 2n + 2
a1 = 2(1) + 2 = 2 + 2 = 4
a2 = 2(2) + 2 = 4 + 2 = 6
a3 = 2(3) + 2 = 6 + 2 = 8
a4 = 2(4) + 2 = 8 + 2 = 10
a5 = 2(5) + 2 = 10 + 2 = 12
Answer:
17
Step-by-step explanation:
