What is the solution 5/2x - 7= 3/4 x + 14 A. x = -6 B. x = 6 C. x = 8 D. x =12

Keith exercises x hours a week. Troy exercises three hours less than Keith and Joe exercises two times more than Troy. Which exp

muminat

If you would like to know which expression represents the amount of time Joe exercises, you can calculate this using the following steps:

Keith ... x hours a week
Troy ... three hours less than Keith: x - 3
Joe ... two times more than Troy: 2 * (x - 3)

The correct result would be D) 2 * (x - 3).

7 0

3 years ago

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Points (−3, 5) and (3, 5) on the coordinate grid below show the positions of two players on a tennis court:

Anna35 [415]

Answer:

4. Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

Step-by-step explanation:

Player 1's position is (-3, 5).

It means that it is 3 units left from the origin and 5 units above the origin.

Player 2's position is (3, 5).

It means that it is 3 units right from the origin and 5 units above the origin.

Hence, the two points are on the same horizontal line bisected by the y-axis.

So, Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

3 0

3 years ago

Sec theta - Csc theta / (csc theta)(sec theta)

Sophie [7]

Answer:

sin(x)-cos(x)

Step-by-step explanation:

$\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)} }{\frac{1}{sin(x)} * \frac{1}{cos(x)} }$

Simplify the denominator:

$\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)} }{\frac{1}{cos(x)sin(x)} }$

Simplify the numerator:

$\frac{{\frac{2(sin(x)-cos(x))}{sin(2x)} } }{\frac{1}{sin(x)} * \frac{1}{cos(x)} }$

Divide the fractions: (a/b)/(c/d) = (a * d)/(b * c):

$\frac{(-cos(x)+sin(x))*2cos(x)sin(x)}{sin(2x)}$

Use the identity: 2cos(x)sin(x) = sin(2x):

$\frac{sin(2x)(-cos(x)+sin(x))}{sin(2x)}$

Cancel out the common factor (sin(2x)):

-cos(x) + sin(x)

Simplify:

sin(x) - cos(x)

3 0

3 years ago

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Can someone please help me with this I really need help. It’s due tonight

ivolga24 [154]

Answer:

12

Step-by-step explanation:

Please mark me as brainlyest

7 0

3 years ago

There are 52 cards in a deck, and 13 of them are hearts. Four cards are dealt, one at a time, off the top of a well-shuffled dec

irga5000 [103]

Answer:

10.97%

Step-by-step explanation:

There are 52 cards.

13 of them, are hearts.

Then

52 - 13 = 39 cards are not hearts.

4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.

So the first card can't be a heart card.

because the deck is well-shuffled, all the cards have the same probability of being drawn.

Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:

p₁ = 39/52

The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:

p₂ = 38/51

For the third card the reasoning is similar to the two above cases, here the probability is:

p₃ = 37/50

The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)

then the probability is:

p₄ = 13/49

The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:

P = p₁*p₂*p₃*p₄

P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097

The percent chance is the above number times 100%

Percent = 0.1097*100% = 10.97%

3 0

3 years ago