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3 years ago

AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to AB ?

Mathematics

1 answer:

Aleksandr [31]3 years ago

3 0

Answer:

3y + 5x = 0

Step-by-step explanation:

The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))

= 5 / -3 = -5/3

Using the point-slope form , the line that passes through the origin and parallel to this line is

y - 0 = -5/3(x - 0)

y = -5/3 x

Multiply through by 3:-

3y = -5x

5x + 3y = 0

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