Answer: 0.00483
Step-by-step explanation:
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
Step-by-step explanation:
Keywords:
System of equations, variables, cost, tickets, adults, children.
For this case we must solve a system of equations with two variables represented by the tickets of students and adults of a school production.
We define the variables according to the given table:
a: Number of tickets sold to adults
c: Amount of tickets sold to children.
We then have the following system of equations:
A + c = 67
10a + 5c =440
From the first equation, we clear the value of the variable c:
C = 67 - a
Answer:
The value that could replace c in the table is:
C = 67 - a
Option C is the answer!
Hope it helped u if yes mark me BRAINLIEST!
Tysm! Plz
M=4
first we take the 4.5 to the other side and we also take the 12 to other side so we get
1.5m=6
we divided each side we get m=4
