So listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry
square 5 and 6
5^2=25
6^2=36
the number betwe 25 and 36
that would be 32
answer is √32
goes like this
5^2<32<6^2
sqrt both sides
5<√32<6
answer is √32
Answer: -7/3≤t≤5/3
Step-by-step explanation:
|2t + 2/3|≤4
2t + 2/3≤4
(2t + 2/3≤4)*3
6t+2≤12
6t≤10
t≤10/6
<u>t≤5/3</u>
2t + 2/3>=-4
(2t + 2/3>=-4)*3
6t + 2>=-12
6t>=-14
t>=-14/6
<u>t>=-7/3</u>
-7/3≤t≤5/3
Answer:
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Given quadratic equation is,
12a² + 9a + 7 = 0
By comparing this equation with standard quadratic equation,
hx² + kx + c = 0
h = 12, k = 9 and c = 7
By using quadratic formula,
a = 
= 
= 
= 
= 
a = 
Therefore, Option B will be the correct option.
Answer:
y-intercept: 5/3
Step-by-step explanation:
Our equation: y = mx + b
Given equation: y = -8/3 + 5/3
=> Now, let's compare.
=> y = mx + b = y = -8/3 + 5/3
=> we can tell that the y-intercept is b, which is 5/3.
Hoped this helped.
