Answer:
Return trip travel time: 7h
Step-by-step explanation:
Let d be the distance.
Index 1 refers to initial trip, index 2 refers to the return trip.
v1=70mi/h
v2=40mi/h
t2=t1+3h, or t1=t2-3h (travel times)
d=v1×t1=v2×t2
v1×(t2-3)=v2×t2
v1 t2 -3 v1=v2 t2
v1 t2 - v2 t2=3 v1
t2(v1-v2)=3v1
t2=3v1/(v1-v2)
Or
t2=3×70/(70-40)=3×70/30=7h
To solve for YW and VX I would use the Pythagorean Theorem. Add 19^2 to 31^2. Your answer should come out to be 1322. Now, find the square root of 1322. Due to the fact that it is not a perfect square, I would round this number. I am not sure if you were given a decimal place to round to, so I will just give you the full number (36.35932) Also, both diagonals are congruent, so ZX would just be half of 36.35932. Again, round the where you are asked to round.
we know that
A quadratic equation is a polynomial with an order of two. Its general form is
case a) 
<u>The case a) is a quadratic equation</u>
case b) 
<u>The case b) is a grade 
polynomial</u>
case c) 
<u>The case c) is a grade 
polynomial</u>
case d) 
<u>The case d) is a grade 
polynomial</u>
therefore
the answer is
I don’t know the answer, but when you get it can you tell me I have a similar problem on my test
Step-by-step explanation:
911
