If Sachiko lets x represent the length of the side of the square and she wants to find the length of the perimeter of the square, it is appropriate for her to ...

... B. Set the area equal to x², solve for x, and then multiply the value of x by 4.

_____

The area of a square of side length x is x·x = x². The perimeter of a square of side length x is x+x+x+x = 4·x.

3 0

3 years ago

Greg has $250 to spend. He wants to buy a new gaming system that is usually $380 but he knows it is on sale. If there is an 8% s

Vadim26 [7]

The correct answer is 38%

5 0

3 years ago

Akiko drew a parallelogram with base of 7 yards and area of 21 square yards. Find its height (nearest tenth). Tahel required

Mrac [35]

Answer:

The height of the parallelogram is 3 yards.

Step-by-step explanation:

A parallelogram has a base of 7 yards, and an area of 21 square yards.

The formula for the area of a parallelogram is A = bh.

So, to find h (the height), that formula becomes h = A/b

h = 21/7

h = 3

The height of the parallelogram is 3 yards.

(Work Check:

A = bh

A = 7 * 3

A = 21)

3 0

3 years ago

Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea

Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

Team A could win all first 4 matches. We can depict this as A-A-A-A
Team A could win 4, while having lost 1. Lets depict this a A-B-A-A-A
Team A could win 4, while having lost 2. A-B-B-A-A-A
Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. $\frac{5!}{4! * 1!}$ = 5

3 $\frac{6!}{4! * 2!}$ = 15

4 $\frac{7!}{4! * 3!}$ = 35

These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.

4 0

4 years ago