To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
The probability of getting a <em>country CD</em> out of all the CDs is the number of <em>country CDs</em> divided by the <em>total number of CDs</em> in Dante's Collection.
The <em>total number of CDs</em> in Dante's collection is
.
The total number of <em>country CDs</em> is 12.
So our required probability is
.
In percentage this is 3 divided by 10, and then multiply by 100. We get 30%. Answer choice D is correct.
ANSWER: D
2.18 that will be ur answer
Answer:
x - y = 3
any values of x& y where x is three greater than y
I.E. x = 8 y = 5
Step-by-step explanation: