Now, since I don't want to actually work hard in class, I fail purposely to stay in normal and not advanced. However this is just a algebraic problem with fractions. Add 2/3 to both sides, (I dont know what that gives you) you then have t = whatever. Hope this helpful! :D <span />
Answer
2x-9
Step-by-step explanation:
A^2 +b^2 =c^2
2^2 + 3^2
4+9=13
The hypotenuse is equal to the square root of 13
<u>Answer:</u>
The yield to maturity of the bonds is 11%
<u>Explanation:</u>
Price at which the bonds is currently trading = 283.30$
Face Value = $1000
Coupon rate = 2%
Hence the coupon bond rate = $1000 ×2%
= 
=$20
Years to maturity: 20 years
Formula used:
=
Where C is the bond coupon rate
F is the face value
P is the price
N is the number of years
=
=11%
The yield to maturity of the bonds is 11%
Answer:
0.4494
Step-by-step explanation:
Given :
marks number of students
20-29 8
30-39 12
40-49 20
50-59 7
60-69 3
The range Coefficient is obtained thus :
Range Coefficient = (Xm - Xl) / (Xm + Xl)
Where ;
Xm = Mid value of highest class = (60+69)/2 = 64.5
Xl = Mid value of lowest class = (20+29)/2 = 24.5
Range Coefficient = (64.5 - 24.5) / (64.5 + 24.5)
Range Coefficient = 40 / 89 = 0.4494
