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pogonyaev
3 years ago
7

Simplify the expression r^-3 s^5 t^2/r^2 st^-2

Mathematics
1 answer:
Hoochie [10]3 years ago
5 0
R/s^5t^r2st-2/r^3
hope this helps










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What is the least common denominator of 1/4, 3/7, 1/11
inna [77]
Alright. One way you can do this is to list multiples of each denominator:

1/4:
4, 8, 12, 16, 20, 24, 28, 32, 36...... and so on

3/7:
7, 14, 21, 28, 35, 42, 49, 57, 63......

1/11;
11, 22, 33, 44, 55, 66, 77, 88......

Keep going until you see the least common denominator!

Now an easier way to do this is by multiplying all of the numbers in the denominator then get the factors:

4*7*11 = 308

And since those are not divisible by a whole number (besides 4 but 308 won't be divisible by 2*7*11)

Therefore 308 is the least common denominator.
6 0
3 years ago
Simplify. 192−−−√ 83√ 643√ 106√ 824−−√
makvit [3.9K]

Answer:

192 - 4√291341371

Step-by-step explanation:

If your question is: 192 - √83(√643)(√106)(√824) - √0

Then you multiply all the √s together and then subtract it from 192. √0 is 0, so you don't have to worry about that.

If your question is to <em>simplify</em> 192 in √ form, then the answer is none of the above. To find the √ form of 192, square it: 192² = 36864. So to simplify 192 in √ form, it would be √36864.

5 0
4 years ago
Isaiah writes an expression with 5 terms. All 5 terms are like terms. How
Goshia [24]

Answer:

1

Step-by-step explanation:

Since all 5 terms are like terms they can all be combined into 1 term. For example, 3x + 8x + 5x + 4x + 19x = ?. Since they all have the term x they can be combined into 39x. That leaves 1 term.

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3 years ago
Generalize the pattern by finding the nth term 2, 6, 12, 20...
Nastasia [14]
32, 38, so on. So its +4 then +8 then +12 +16 +20....
8 0
3 years ago
What are the period and amplitude of the function?
umka2103 [35]

Answer:

The period of function is 5 and amplitude is 3.

Step-by-step explanation:

<em>The period of the function is the time interval after which it repeats itself.</em>

It means the time interval after which the same value of graph is attained.

In the above case looking at the peak point at time 5 seconds, the same value is obtained at time 10 seconds.

Thus the time interval is (10 - 5) 5 seconds.

<em>Amplitude is the maximum value attained by the graph in the complete interval.</em>

In the above case, the maximum value attained is 3.

8 0
3 years ago
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