Answer:
Brainly.in
Question
When <u>6</u><u> </u><u>times</u><u> </u><u>a</u><u> </u><u>number</u><u> </u> is increased by 11 the result is 16 less than 9 times the number. Find the number.
Answer · 7 votes
Answer:6x+11=9x-163x=27X=9 Please mark it brainliest
Step-by-step explanation:
Please mark it brainliest
9514 1404 393
Answer:
a) 600
b) see below
c) 1.26 hours
Step-by-step explanation:
a) The value of y when x=0 is the coefficient of the exponential term:
y = 600·3^(-0) = 600·1 = 600
There were 600 atoms to start.
__
b) see attached for a graph
__
c) The graph shows 150 atoms at t = 1.26, about 1.26 hours after the start of time counting.
If you want to find that value algebraically, substitute for y and solve for x. Logarithms are involved.
150 = 600·3^(-x)
150/600 = 3^(-x)
log(1/4) = -x·log(3)
x = -log(1/4)/log(3) = log(4)/log(3) ≈ 1.2618595
After about 1.26 hours, there were 150 atoms.
In order to find the slop it is probably best to put the equation in y=mx+b form. This means to get y by itself on one side.
24x-9y=63 will then become -9y=63-24x in which y has been isolated.
Then you should divided by -9 to get the final form: y=24x/9 -63/9.
Now you can get the slope of the perpendicular line by taking the slope of the original equation and finding its reciprocal which is -9/24x. This is your answer.
Answer:

Step-by-step explanation: