So to put them in intervals of 5 you would have:
70-74
75-79
80-84
85-89
90-94
95-99
In these intervals you would have:
70-74: 72
75-79: 78
80-84: 81
85-89: 86, 86, 87
90-94: 92, 92, 92
95-99: 98
The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)
Shiii it could be answer c
Umm simplified it would be 30t=s. 6*5t=s
We know that both groups feed grass hay in the morning, so that's 100/100.
First group feeds alfalfa and grass in the evening
Second group feeds alfalfa and oat hay in the evening.
The estimated probability that horse owners feed grass hay the morning (AM) is 100%.
The estimated probability that horse owners feed alfalfa + oat hay in the pm is 28/100 or 28% (C)
So x=x
and y=pounds
when x=0, y=64
when x=1, y=63.1
to find slope, (y1-y2)/(x1-x2)=(64-63.1)/(0-1)=0.9/-1=-0.9=slope
y=-0.9x+b
subsitute
64=-0.9(0)+b
b=64
y=-0.9+64
so int 2001, x=11
y=-0.9(11)+64
y=-9.9+64
y=54.1
