Answer: D
Step-by-step explanation:
Just do 7 x 88 LOL
Answer:
D
Step-by-step explanation
I'd say it's PQR and TSR cause they match up in terms of the order of vertexes, and then you've got the angles of P and T that are in the middle of PR and TR, which are equal, and the sides PQ and TS. The angles are in between the sides.
The answer is six and two out of seven or 6 and two sevenths
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
Answer:
9x
Step-by-step explanation:
