All categories

2 years ago

What is the arc length of a segment of a circle with a central angle of 165 and a radius of 3 inches?

Mathematics

2 answers:

Archy [21]2 years ago

7 0

I hope this will help you

san4es73 [151]2 years ago

3 0

Remark
The circumference of a circle is 2*pi*r. The angle the radius will move through is 360 degrees if the radius swings away from it's starting point and goes around the circle until it winds up back at its starting point. If it only goes part of the way, (in this case 165 degrees), then the circumference formula has to be modified.

Formula
Arc Length = (given central Angle/ 360) * 2 * pi * r is the partial distance around the circle.

Sub and solve
Arc length = (165/360) * 2* pi * r
Arc length = (165/360) * 2 * pi * 3
Arc length = 11/24 * 6 * pi
Arc length = 66/24 * pi What you do from here depends on what you have been given. This is one answer.

Another is 8.64 using 3.14 for pi. Please list your choices if there are any. If it is your custom to give out Brainliests, give it to the other responder. I forgot the 2 and had to edit it.

You might be interested in

Plz help!!

garri49 [273]

Answer:

150 ft^3

.1 ton or 200 lbs

Step-by-step explanation:

The volume is given by

V = l*w*h

V = 5*5*6

V = 150 ft^3

To find how much 1 ft^3 weighed take the weight and divide by the volume

15 tons / 150 ft^3

.1 ton / 1 ft^3

1 ft^3 weights .1 ton

We know that 1 ton = 2000 pounds

.1 ton = 200 pounds

4 0

2 years ago

Read 2 more answers

PLSSS HELP IF YOU TURLY KNOW THISS

Galina-37 [17]

Answer:

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers

Yolanda has a box that contains 8 3/4 dozen beads. She uses 3 1/4 dozen beads for a necklace and 1 3/4 dozen beads for a bracele

Artyom0805 [142]

Answer:

The answer is a bit c d

3 0

1 year ago

Read 2 more answers

Need help due tmr please and thank you :)

Katena32 [7]

10. After all the Pythagorean theorem the answer is 51.7215 cm

3 0

2 years ago

T is a pesticide banned in the United States for its danger to humans and animals. In an experiment on the impact of DDT, six ra

Kruka [31]

Answer:

$SE =\sqrt{\frac{s^2_{P}}{n_{P}}+\frac{s^2_{UP}}{n_{UP}}}$

And if we replace we got:

$SE =\sqrt{\frac{(6.34)^2}{6}+\frac{(1.95)^2}{6}}}=2.708$

Step-by-step explanation:

1) Data given and notation

P:[12.207 ,16.869, 25.050, 22.429, 8.456, 20.589]

UP:[11.074, 9.686 ,12.064, 9.351, 8.182, 6.642]

$\bar X_{P}=17.6$ represent the mean for the sample poisoned

$\bar X_{UP}=9.50$ represent the mean for the sample unpoisoned

$s_{P}=6.34$ represent the sample standard deviation for the sample poisoned

$s_{UP}=1.95$ represent the sample standard deviation for the sample unpoisoned

$n_{P}=6$ sample size for the group poisoned

$n_{UP}=6$ sample size for the group unpoisoned

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for rats exposed to DDT is greater than that for rats not poisoned , the system of hypothesis would be:

Null hypothesis: $\mu_{P} \leq \mu_{UP}$

Alternative hypothesis: $\mu_{P} > \mu_{UP}$

If we analyze the size for the samples both are less than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{P}-\bar X_{UP}}{\sqrt{\frac{s^2_{P}}{n_{P}}+\frac{s^2_{UP}}{n_{UP}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

The standard error is given by:

$SE =\sqrt{\frac{s^2_{P}}{n_{P}}+\frac{s^2_{UP}}{n_{UP}}}$

And if we replace we got:

$SE =\sqrt{\frac{(6.34)^2}{6}+\frac{(1.95)^2}{6}}}=2.708$

3) Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{17.6-9.5}{\sqrt{\frac{(6.34)^2}{6}+\frac{(1.95)^2}{6}}}}=2.99$

4) Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{P}+n_{UP}-2=6+6-2=10$

Since is a unilateral test the p value would be:

$p_v =P(t_{(10)}>2.99)=0.0067$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to don't reject the claim that the group with DDT have a mean greater than the group for rats not poisoned.

3 0

2 years ago