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tatyana61 [14]
3 years ago
10

Rauol measured the height of 12 different plants in his garden in April. He measured them again in June. What is the difference

between the mean height in April and the mean height in June?
Mathematics
1 answer:
jasenka [17]3 years ago
3 0

The question is incomplete. Here is the complete question.

Raoul measured the ehight of 12 different plants in his garden in April. He measured them again in June.

April Heights (in inches) 12 15 23 11 42 45 44 39 12 19 20 12

June Heights (in inches) 45 45 40 43 11 14 12 13 41 40 45 41

What is the difference between the mean height in April and the mean height in June?

Answer: The difference between means is 8.0

Step-by-step explanation: <u>Mean</u> is the average of a set of numbers.

It is calculated as:

\mu=\frac{\Sigma x}{n}

where

x is the numbers in the set

n is how many numbers are there in the set

For heights in April, the mean is:

\mu_{1}=\frac{12+15+23+11+42+45+44+39+12+19+20+12}{12}

μ₁ = 24.5

For heights in June, the mean os:

\mu_{2}=\frac{45+45+40+43+11+14+12+13+41+40+45+41}{12}

μ₂ = 32.5

The difference between means:

μ₂ - μ₁ = 32.5 - 24.5 = 8.0

The difference between the mean height in April and in June is 8.0 inches.

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motikmotik

Answer:

We conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

  • Base = p+1
  • Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

                                            =\frac{1}{2}\left(p+1\right)\left(2p-6\right)

Factor 2p-6: 2(p-3)

                                             =\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}  

Divide the number: 2/2 = 1

                                              =\left(p+1\right)\left(p-3\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

                                               =pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)

                                               =pp-3p+1\cdot \:p-1\cdot \:3

                                                =p^2-2p-3

Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

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3 years ago
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