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coldgirl [10]
3 years ago
7

from a group of 6 candidates, a committee of 2 people is selected. in how many different ways can the committee be selected?

Mathematics
1 answer:
butalik [34]3 years ago
6 0
6 choose 2
6C2 = 6!/(2!(6-2)!)
=6!/(2!4!)
=6•5/2
=15
The answer is 15 ways.
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The bag has 2 yellow cubes, 5 green cubes, and 3 red cubes. Without replacing the yellow cube, what is the probability of select
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32% chance of selecting red at random.
3 0
3 years ago
A cone has volume 12 cubic inches. Its radius is 2 inches. What is its height?
Paladinen [302]

Answer:

h≈2.86

Step-by-step explanation:

8 0
3 years ago
Write a + - x or ÷ sign in each box to make the equation true <br><br> 7 18 45 3 2 = 139
irina [24]
I mean, I don't know how to explain a generic way to solve this. Ask me about the specific train of thought if you are interested:

7 * 18 + 45 / 3 - 2 = 139
4 0
4 years ago
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
3 years ago
Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.
evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) (5^2)(5^3)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

5^2\times 5^3=5^{2+3}=5^6=15625

(b) (5^2)(5^{-3})

So, it becomes,

5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2

(c) (5^2)^2

As we know that

(a^m)^n=a^{mn}

So, it becomes,

5^{2\times 2}=5^4=625

(d) 5^{-3}

a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

4 0
3 years ago
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