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Bess [88]
3 years ago
6

5 less than a number is no more than 12

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0
The answer should be 6 bro
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Let $f(x) = 12x^9 + x$. Find $f(3) + f(-3)$.
BlackZzzverrR [31]

Answer:

Ok, here goes:  f(3) means take f(x) and plug in 3 wherever we see x.  So

f(3) = 12*39 + 3 = 236196 + 3

f(3) = 236199

Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x.  So

f(-3) = 12*(-3)9 + (-3) = -236196 - 3

f(-3) = -236199

Putting those two things together, we get

f(3) + f(-3) = 236199 - 236199 = 0

Step-by-step explanation:

7 0
2 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
How do i solve f(x)=|x-2|+3
Olenka [21]

Answer:

f(x)=|x-2|+3

0=|x-2|+3

0-3=|x-2|+3-3

-3+2=x-2+2

-1=x

Step-by-step explanation:

  1. set the function equal to zero
  2. you can subtract 3 from both sides or you can add -2 and 3 and then you subtract your answer from both sides to solve for x
7 0
3 years ago
Can someone help with this please??​
adoni [48]

Answer:

doesn't x equal 6 too?

Step-by-step explanation:

since x is the same size as the other side of the triangle

8 0
3 years ago
Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 12 in., 24 in., 48 in.B. 12 in., 6 in
bearhunter [10]
C. And it would be a equilateral
5 0
3 years ago
Read 2 more answers
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