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1 year ago

"Based on the following construction, which of the following are true? choose all that apply."

Mathematics

1 answer:

umka21 [38]1 year ago

4 0

From the diagram,

Angle

Bisecting an angle means dividing the angle into two equal part.

1/2 m

$\begin{gathered} \text{ } \\ \\ \end{gathered}$

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PLEASE HELP QUICK!!<br> How far will a plane travel in 6 hours if it travels at 70 miles per hour?

svetoff [14.1K]

Answer:

420 miles

Step-by-step explanation:

brainly.com/question/17501583 go to this link and link my answer plz. First 100 gets a free follow!

8 0

3 years ago

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Subtract:<br> 7' 5" – 2' 8" =

yKpoI14uk [10]

Answer:

4'9"

Method 1:

First, convert both numbers into inches. Remember that 1' = 12", and the rest is like a remainder.

7'5" = (7*12)+5 = 84+5 = 89

2'8" = (2*12)+8 = 24+8 = 32

Next, subtract the two numbers.

89 - 32 = ?

89 - 32 = 57

There's your answer! You can change it back into feet by dividing it by 12.

57 / 12 = 4.75 = 4'9"

Method 2:

Another way of solving this problem is to borrow from the "feet" place.

7'5" - 2'8"

You can't take 8 away from 5, so you borrow from the "feet" place. Remember that unlike normal borrowing, you need to add 12 instead of adding 10.

6'17" - 2'8" = 4'9"

Whichever method you choose, you should get the same answer!

5 0

3 years ago

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Can anyone please help me thank you

kondor19780726 [428]

Answer:

[2, 4]

Step-by-step explanation:

[2, 4]

3 0

3 years ago

Two corporate baseball teams are scheduled to play a game together. They agree that if both teams attend or if neither team atte

sp2606 [1]

Answer:

2.99% probability that the cost will be paid by only one team

Step-by-step explanation:

The binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that a team plays:

A team plays if it has at most 2 injured players out of 11.

11 players, so $n = 11$

Each player with a 5% probability of injury, so $p = 0.05$

Then

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{11,0}.(0.05)^{0}.(0.95)^{11} = 0.5688$

$P(X = 1) = C_{11,1}.(0.05)^{1}.(0.95)^{10} = 0.3293$

$P(X = 2) = C_{11,2}.(0.05)^{2}.(0.95)^{9} = 0.0867$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5688 + 0.3293 + 0.0867 = 0.9848$

Each team has a 0.9848 probability of showing up to play.

What is the probability that the cost will be paid by only one team?

This happens if one team shows up and the other do not.

2 teams, so $n = 2$

Each team has a 0.9848 probability of showing up to play, so $p = 0.9848$ .

This probability is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.9848)^{1}.(0.0152)^{1} = 0.0299$

2.99% probability that the cost will be paid by only one team

7 0

4 years ago

AYE HELP ASAP PLZ!!!!!

Aleks [24]

It's the first one you can just add or multiply the expressions to get the answer

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3 years ago

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