Hold on just have to type before I can see the question
Answer:
Step-by-step explanation:
cos (x/2)=cos x+1
cos (x/2)=2cos ²(x/2)
2 cos²(x/2)-cos (x/2)=0
cos (x/2)[2 cos (x/2)-1]=0
cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)
x/2=2nπ+π/2,2nπ+3π/2
x=4nπ+π,4nπ+3π
n=0,1,2,...
x=π,3π
or x=180°,540°,...
180°∈[0,360]
so x=180°
or
2cos(x/2)-1=0
cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)
x/2=360n+60,360n+300
x=720n+120,720n+300
n=0,1,2,...
x=120,300,840,1020,...
only 120° and 300° ∈[0,360°]
Hence x=120°,180°,300°
Answer:

Step-by-step explanation:
The equation of the line with the slope
and passing through the point
is

In your case,

Hence, the equation of the line is

I Have made a table for you. You start by making a table, <span>To graph with a table you simply pick numbers for </span>x<span> and solve for </span>y<span> by plugging </span>x<span> into the equation. This gives you the points to graph.</span>
Hi there!

Use the Pythagorean theorem to find the length of the line.
If we draw an imaginary right triangle using the given line as the hypotenuse, we can derive a height of 6 units and a length of 10 units.
Use the Pythagorean theorem equation:
c² = a² + b²
Plug in the height and length:
c² = 6² + 10²
Simplify:
c² = 36 + 100
c² = 136
Take the square root of both sides:
c = √136. The correct answer is D.