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Talja [164]
3 years ago
14

What is the value of x in the equation

Mathematics
2 answers:
kogti [31]3 years ago
5 0

Answer:

x = 27

Step-by-step explanation:

3x - 4(4) = 65

3x - 16 = 65

3x = 81

x = 27

kow [346]3 years ago
3 0
X=27 that’s the answer
You might be interested in
Please help with simple probability question. Extra points & brainliest. Thanks in advance.
kodGreya [7K]
The answer is B) 1/3.

There are 6 faces on a rectangular prism, each of which is a rectangle.  

The area of the front and back is given by 25(8) = 200 sq. cm.
The area of the bottom and top is given by 25(4) = 100 sq. cm.
The area of the right and left is given by 4(8) = 32.

There are 2 faces out of 6 with an area that is not a multiple of 100; 2/6 = 1/3.
3 0
3 years ago
Sorry i ment to put 14/15 - 1/3 then put as a fraction in simplest form
Sergio039 [100]

Answer:

Step-by-step explanation:

14/15 - 1/3

= 6/10

In simplest form

= 3/5

7 0
2 years ago
Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu
Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4a^{4} - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u²  - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = \frac{1}{4}

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

a² = \frac{1}{4} ⇒ a = ± \frac{1}{2}

Solutions are a = ± 1 , a = ± \frac{1}{2}

7 0
3 years ago
8=4y-8+4 solve the equation
Yuliya22 [10]

Answer:

y=3

Step-by-step explanation:

4y-8+4=8

4y-4=8

4y-4+4=8+4

4y=12

4y/4=12/4

y=3

3 0
3 years ago
Read 2 more answers
Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

8 0
3 years ago
Read 2 more answers
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