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Inessa05 [86]
3 years ago
14

How can I make 8 and 62/40 a proper mixed number

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
You can't make it proper.You can only simplify.
Step 1: Factor both the numerator and denominator down to prime factors:<span>62 = 2 * 31 </span>
40 = 23<span> * 5</span>Step 2: Calculate the greatest common factor, GCF (also called greatest common divisor, GCD), by taking all the common prime factors of the numerator and denominator, by the lowest powers:gcd(2 * 31; 23<span> * 5) = </span><span>2 </span>
Step 3: Divide both the numerator and denominator by their greatest common factor, GCF (also called the greatest common divisor, GCD):62/40 =
(2 * 31)/<span>(23 * 5)</span> = 
<span>((2 * 31) : 2)</span> / <span>((23 * 5) : 2)</span> =
31/<span>(22 * 5)</span> =
31/20Step 4: Improper fraction, rewrite:<span>31 : 20 = 1 and remainder = 11 => </span>
31/20<span> = </span>(1 * 20 + 11)<span> / </span>20<span> = 1 + </span>11/20<span> = 1 </span>11/20<span> as a </span>mixed number (also called mixed fraction).<span>1 + 11 : 20 = 1.55 as a </span>decimal number<span>.</span>
slavikrds [6]3 years ago
3 0
First you change 62/40 to a proper mixed number: 1 11/20

then you add 8 to 1 11/20 :

your final answer is 9 11/20


hope this helps :)


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