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3 years ago

PLEASE HELP ASAP!! SPAM ANSWERS WILL BE REPORTED. I REALLY APPRECIATE IT

Mathematics

1 answer:

Advocard [28]3 years ago

4 0

i think it's linear -2, y intercept = 35. it's like 35 every 2 minutes, i think I might be wrong sorry

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How would you find the values of x and y?

Ipatiy [6.2K]

If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.

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3 years ago

This is Hard for me!

max2010maxim [7]

DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
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3 years ago

What is the sixth term of the sequence shown in the table

horsena [70]

Answer:

375

Step-by-step explanation:

trust me

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3 years ago

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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

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3 years ago

Solve the equation for y. 1/3x+y=4

OLEGan [10]

1/3x + y = 4....subtract 1/3x from both sides
y = -1/3x + 4 <===

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3 years ago

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