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Volgvan
2 years ago
10

Which graph represents an even function?​

Mathematics
2 answers:
expeople1 [14]2 years ago
5 0

Answer:

Step-by-step explanation:

The first graph (the parabola opening down) represents an even function, since this graph is symmetric with respect to the y-axis.

joja [24]2 years ago
4 0
<h2>First graph represents an even function</h2>

Step-by-step explanation:

For an even function we have f(x) = f(-x)

In the given graphs let us substitute values

In first graph

            f(2) = 0

            f(-2) = 0

            So f(2) = f (-2)

            Graph is even

In second graph

            f(2) = 0

            f(-2) = 4

            So f(2) ≠ f (-2)

            Graph is not even

First graph represents an even function

You might be interested in
Please answer immediately!!!!!!!!
Westkost [7]

Answer:

For tree see picture but instead of BG replace all values with RRBBB and see the notes above how to roate the colours instead of the shape roation below just do transition (0,0)(1,0) (1,1).

Then 13 colours minimum change.

This will be 3 + 5 + 4 each colour change = 12 each colour change. instead of doing the 56 each colour rotation below.

Step-by-step explanation:

make 4 bits of paper and label each side -1 and 1 and central 0

above central point vertically label 1 and -1 for transition.

Then change just top one 4x = 4 more

Do the same with 2nd from top = 8 more to include top changing 4x again.

Do the same with 2nd from bottom = 12 more

Do the same with bottom = 16 more.

4+8+12+16 =40

Then repeat the process on side for blocks and we can double up

40+40 = 80.

When drawing tree clearly state columns

Top two are red only change

Top of tree will read in order so where ever you see capital R you will know its a new column for the tree and fill in when you understand the 254 transitions of a 5 column tree. Then change B + R accordingly when you get to row 6. Here you just start changing blue back to the top after row 5

Columns go down and rows go across its a new row you will need

approx 5-6 rows each colour change.

For the ones started for you below its just transition and colour stays where it is.  

R x    RT 45d   RT (1,0) 45   RT (1,1) 45  RT (1,0)

R x    R x

B x    B x

B x    B x

B x    B x

'x' = RED Normal as you keep 0 zero central on all 4 bricks and work with top row as explained below.

Top RED  brick you have to Right side place transition on every 2nd column for each colour and thenyou should find a pattern if youve numbered your papers or brcks to just see how it works. (hanging out one side call this 'off set' or call it T for transition (1.0)

RED Central 'diagonal' call it  '45 degree rotate'

E ABCD RED Normal edge transition its edge so it hangs out

E ABCD RED On edge 45 degree diagonal its edge so it hangs out

2nd only change

S ABCD 1st red normal 2nd red Right side place rotate

S ABCD 1st red right side rotate 2nd red 45 degree rotate

S ABCD 1st red right side rotate 2nd central place 45 degree rotate  

S ABCD 1st red right side rotate 2nd edge Normal edge transition

S ABCD 1st red right side rotate 2nd 45 degree its edge diagonal

2nd is repeated by changing 1st 4x more in bold. see what is now missing for 1st red. and copy the 2nd changes to 1st all whilst rotaing 2nd again in change .

Copy paste the work

Then apply this to 3 + 4 + 5th brick.

As the above shows 10 and when you finish 2nd and 1st it will be 14 total

Then 3 will be 14 again

and 4th brick will be 14 again

and 5th brick will be 14 again

making the transitions and rotations where all bricks in same level placement

14 x 4 = 56 transitions/rotations

Then repeat again for 1 blue at the top change

Then repeat again for 2 blue at the top for change

Then repeat again for 2 blue in the top middle

Then repeat again for 2 blue in the bottom middle

You can label tree

RR = Red rotation

BR = Blue rotation

RRE= Red rotation edge

BRE = Blue rotation

and colour code blue and red pens.

You can label transitions

RT = red transition (1,0)

RT = red transition (1,1) for central

and same for blue etc..

The end result will be 56 x 4 = 224 diagram tree

On ce you learn this it will take just 6 minutes to write out.

6 0
2 years ago
What is the length of line segment KJ?
Karolina [17]

Please consider the attached file.

We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.

We will use Pythagoras theorem to solve for KJ as:

KJ^2=KM^2+MJ^2

KJ^2=6^2+3^2

KJ^2=36+9

KJ^2=45

Now we will take positive square root on both sides:

\sqrt{KJ^2}=\sqrt{45}

KJ=\sqrt{9\cdot 5}

KJ=3\sqrt{5}

Therefore, the length of line segment KJ is 3\sqrt{5} and option D is the correct choice.

5 0
3 years ago
Micheal has been awarded a pay rise of 4%.His salary is £ 24 492 <br> What was his apart before?
Nesterboy [21]
Because there was a pay rise, we can write the equation as x+0.04x = 24.492 and solve for x.

x+0.04x = 24.492
1.04x = 24.492
x=23.55

His original pay was £23.55
6 0
3 years ago
7.9 - 4.012. I really don't know the answer
Lunna [17]
3.888 :))))))))))))))))))))))))))
7 0
3 years ago
Please help me match this
Setler [38]
4/5=0.8
0.35=7/20
3/8=0.375
0.775=31/40

You could have use a calculator for this but you’re welcome
8 0
3 years ago
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