Answer:
u = -5/9
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-3(u + 2) = 5u - 1 + 5(2u + 1)
<u>Step 2: Solve for </u><em><u>u</u></em>
- Distribute: -3u - 6 = 5u - 1 + 10u + 5
- Combine like terms: -3u - 6 = 15u + 4
- Add 3u to both sides: -6 = 18u + 4
- Subtract 4 on both sides: -10 = 18u
- Divide 18 on both sides: -10/18 = u
- Simplify: -5/9 = u
- Rewrite: u = -5/9
<u>Step 3: Check</u>
<em>Plug in u into the original equation to verify it's a solution.</em>
- Substitute in <em>u</em>: -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
- Multiply: -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
- Add: -3(13/9) = -25/9 - 1 + 5(-1/9)
- Multiply: -13/3 = -25/9 - 1 - 5/9
- Subtract: -13/3 = -34/9 - 5/9
- Subtract: -13/3 = -13/3
Here we see that -13/3 does indeed equal -13/3.
∴ u = -5/9 is a solution of the equation.
Answer:
103,000
Step-by-step explanation:
Use your knowledge of decimal arithmetic. Or, use a calculator.
100,000(1 +.03) = 100,000·1.03 = 1000·103 = 103,000
Answer:
the shaded area is 26, the non-shaded area 16
Step-by-step explanation:
The red shaded lines had numbers as well so I add all of them up.
The non-shaded lines didn't have a number, but the bottom had the same length of the top line so therefore your answer is 26 for Shaded, and 16 for non-shaded.
Answer:
Distance between boat and light house = 223.88 meter (Approx.)
Step-by-step explanation:
Given:
Height of light house = 60 meters
Angle of depression to boat = 15°
Find:
Distance between boat and light house
Computation:
Using trigonometry application:
Tanθ = Perpendicular / Base
Tan 15 = Height of light house / Distance between boat and light house
0.268 = 60 / Distance between boat and light house
Distance between boat and light house = 60 / 0.268
Distance between boat and light house = 223.88 meter (Approx.)
