Answer:
Step-by-step explanation:
Given that the hartford insurance company has hired you to poll a sample of adults about their car purchases.
Here the insurance company is using convenience sampling to select customers so they resorted to taking the names from telephone directories.
But this may not be reliable since persons owning cars need not have telephones and similarly persons having telephones need not own cars
Owning a car and name appearing in telephone directory need not be associated at all
So taking random sample of names from telephone directories may not give the required accurate result since here sample cannot be assumed to represent the population of car owners.
Answer:
Markup: $9 ; Selling Price: $24
Step-by-step explanation:
The store makes a profit of $15, to find the mark up of 60%, multiply 15 x 60%.
15 x 0.6 = 9
Add the markup price to the original price.
9 + 15 = $24
The selling price is $24
Answer:
The answer would be C because b=+16 which means that it intercepts line y at 16, which is shown in the graph.
Step-by-step explanation:
Answer:
The answer is "Option A and Option B".
Step-by-step explanation:
In question 1:
In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.
This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.
In question 2:
When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.
X² - 3x - 10
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>