Question

A stone is thrown straight up from the edge of a roof, 725 feet above the ground, at a speed of 16 feet per second. C. What is the velocity of the stone when it hits the ground?

Answer 1

Answer:

216 ft/s.

Step-by-step explanation:

Displacement (s) =  -725 ft

Initial speed (u) = 16 ft/s

Acceleration due to gravity (g) = -32 ft/s/s.

We can use the equation of motion v^2 = u^2 + 2gs

v^2 = 16^2 + 2 * -32 * -725

v^2 = 256 + 46400

v^2 = 46,656

V = 216 ft/2.