Given:
The quadratic equation is:
It can be written as .
To find:
The value of p in the rewritten equation.
Solution:
We have,
Isolate the constant term.
We need to make 202 on the right side. So, add 256 on both sides.
Let , then
Therefore, the value of p is .
The given equation can be written as:
Adding 148 on both sides, we get
Let , then
Therefore, the another possible value of p is .
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Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.