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Verizon [17]
3 years ago
8

How would I go about solving this problem?

Mathematics
1 answer:
saul85 [17]3 years ago
5 0
I started by finding the area of the walls. The 8x10 walls are 80 and there are 2 so 160. And the other walls are 15x8 so 120 and there are 2 so 240. I added 160 and 240 to get 400. Then you need to subtract the window and the door because you aren’t painting them. You end up getting 340
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. A man travels 13km by bus , 8km by car and y km by train . If the man has to travel a total of 30 km , find y. *
erma4kov [3.2K]

Answer:

9km

Step-by-step explanation:

30-(13+8)=9km

I hope you understand

6 0
3 years ago
What is 21-10+10-5-3+2+21-36+21<br> correct answers get a free cookie
Tcecarenko [31]

Answer:

uh its 5

Step-by-step explanation:

3 0
3 years ago
Help ASAPPPPP ALGEBRA 2
castortr0y [4]

This is cross multipication.  Multiply 117 times 36 together for that you would use a calculator. You get 4221. Next step is to multiply x and 12 together that would be 12x.

4221= 12x

Divide  by 12 on both sides:

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351 is # of trouts in the lake .

4 0
3 years ago
X=4-2y<br> 3x-2y=4 Substitution
ollegr [7]

Answer:

<h2>The solution is x = 2 and y = 1.</h2>

Step-by-step explanation:

The given equations are x = 4 - 2y.......(1) and 3x - 2y = 4......(2).

Putting the value of the first equation in the second, we get

3x - 2y = 4

or, 3(4 - 2y) - 2y = 4

or, 12 - 6y - 2y = 4

or, 8y = 8

or, y = 1.

Putting the value of y in the first equation, we get x = 4 - 2 = 2.

8 0
4 years ago
Read 2 more answers
Write the sum of the numbers as the product of their GCF and another sum 64+28 PLEASE ANSWER QUICKLY
zepelin [54]

64 and 28 have a GCF of 4, since 64 = 4 x 16, 28 = 4 x 7, and 7 and 16 have no factors other than 1 in common. Knowing that, we can rewrite 64 + 28 as

4 x 16 + 4 x 7

and then use the distributive property to rewrite it again as

4 x (16 + 7)

5 0
3 years ago
Read 2 more answers
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