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4 years ago

A is a 3x3 matrix with det(A) = 4. Find det(adj(A)).

Mathematics

1 answer:

iris [78.8K]4 years ago

8 0

Answer:

The value of det(adj(A)) is 16.

Step-by-step explanation:

It is given that A is a 3x3 matrix with det(A) = 4.

We need to find the value of det(adj(A)).

We have a formula

$det(adj(A))=(det(A))^{n-1}$

where, n is order of the square matrix.

Substitute det(A) = 4 and n=3 in the above formula.

$det(adj(A))=(4)^{3-1}$

$det(adj(A))=(4)^{2}$

$det(adj(A))=16$

Therefore, the value of det(adj(A)) is 16.

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4 years ago

A rectangle has a length of x + 7 and a width of x-2. Which equation below describes the perimeter, P, of

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3 years ago

Which of the following is the result of the equation below after completing the square and factoring?

Tems11 [23]

Answer:

D) $(x + \frac{5}{2})^{2} = \frac{9}{4}$

Step-by-step explanation:

Step(i):-

Given equation

x² + 5 x + 8 = 4

⇒ $x^{2} + 2 X \frac{5}{2} x + (\frac{5}{2} )^{2} - (\frac{5}{2} )^{2}+ 8 = 4$

Step(ii):-

By using (a + b)² = a² + 2 a b + b²

⇒ $(x + \frac{5}{2})^{2} - (\frac{5}{2} )^{2}+ 8 = 4$

⇒ $(x + \frac{5}{2})^{2} = 4 + (\frac{5}{2} )^{2} -8$

⇒ $(x + \frac{5}{2})^{2} = (\frac{25}{4} ) -4$

⇒ $(x + \frac{5}{2})^{2} = (\frac{25-16}{4} )$

⇒ $(x + \frac{5}{2})^{2} = \frac{9}{4}$

Final answer:-

$(x + \frac{5}{2})^{2} = \frac{9}{4}$

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3 years ago