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adell [148]
1 year ago
11

Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Mathematics
1 answer:
Aleonysh [2.5K]1 year ago
5 0

Given:

f\mleft(x\mright)=e^{-x^3}

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}

Thus, y = 0 is the horizontal asymptote for the given function.

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If students’ scores were normally distributed and the mean was 200 with a standard deviation of 40, then what is the probability
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Y=2x-10 substitution <br> Y=4x
Arada [10]
X=5
 Work:

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4 0
4 years ago
Diane has the following data:
Vladimir [108]
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9, 9, 10, 11.
9, 10.
9.5 is our median currently.
Since we need to get a number after 10 to make 10 the median, let's use 12.
8, 9, 9, 9, 10, 11, 12, 12, 15.
9, 9, 9, 10, 11, 12 ,12.
9, 9, 10, 11, 12.
9, 10, 11.
10 is now our median since we inserted 12 into our list.
Your answer is 12.
I hope this helps!
3 0
3 years ago
The universal set in this diagram is the set of integers from 1 to 15. Place the integers in the correct place in the venn diagr
alexira [117]

Answer:

The universal set in this diagram is the set of integers from 1 to 15. Place the integers in the correct place in the venn diagram

Step-by-step explanation:

this is the answer

5 0
2 years ago
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