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adell [148]
1 year ago
11

Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Mathematics
1 answer:
Aleonysh [2.5K]1 year ago
5 0

Given:

f\mleft(x\mright)=e^{-x^3}

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}

Thus, y = 0 is the horizontal asymptote for the given function.

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Law of sines formula
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3 years ago
Jay makes a base salary of $2000 per month. Once he reaches $50000 in total sales, he earns an additional 5% commission (salary)
ki77a [65]

Answer:

j(s) = 0.05s -500

Step-by-step explanation:

Given

Base\ Salary = 2000

Commission = 5\% on Sales over 50000

Required

Determine the function j(s) for sales over 50000

Represent the total sales in a month with s.

Sales over 50000 in that month will be: s - 50000

So, the function j(s) is:

j(s) = Base Amount + Commission * Sales over 50000

j(s) = 2000 + 5\% * (s - 50000)

Convert % to decimal

j(s) = 2000 + 0.05 * (s - 50000)

Open bracket

j(s) = 2000 + 0.05 * s - 0.05 * 50000

j(s) = 2000 + 0.05s - 2500

Collect Like Terms

j(s) = 0.05s - 2500 + 2000

j(s) = 0.05s -500

3 0
3 years ago
Solve the system of equations.<br> – 9y + 4x – 11 = 0<br> - 3y + 10x + 31 = 0
Kruka [31]

value of x =-4 and value of y=-3

(-4,-3) is the solution of system of equations.

Step-by-step explanation:

We need to solve the system of equations

-9y + 4x-11 = 0- 3y + 10x + 31 = 0

Rearranging:

-9y + 4x = 11\,\,\,eq(1)\\- 3y + 10x=- 31 = 0\,\,\,eq(2)

Multiply eq(2) with 3 and subtract eq(2) from eq(1)

-9y + 4x = 11\\-9y+30x=-93\\+\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\-26x=104\\x=\frac{104}{-26}\\x=-4

Putting value of x = -4 into eq(1)

-9y + 4x = 11\\-9y+4(-4)=11\\-9y-16=11\\-9y=11+16\\-9y=27\\y=\frac{27}{-9}\\y=-3

So, value of x =-4 and value of y=-3

(-4,-3) is the solution of system of equations.

Keywords: system of equations.

Learn more about system of equations at:

  • brainly.com/question/6075514
  • brainly.com/question/7490805
  • brainly.com/question/13168205

#learnwithBrainly

5 0
3 years ago
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