Ok so from experience on this site
3x2=3x^2
people don't know how to put exponents
3x^2-y^3-y^3-z
simplify first
3x^2-2y^3-z
x=3
y=-2
z=-5
3(3^2)-2(-2)^3-(-5)
3(9)-2(-8)+5
27+16+5
48
Subtract 9/4 from both sides
3/4x=6 3/4
Multiply them by 4/3
X=9
use the midpoint formula. It's x1 + x2 / 2, y1+y2/2. When you solve you get (0, 1/2) is the midpoint. Hope this helps
Hello from MrBillDoesMath!
Answer:
See below
Discussion:
Triangles BAD and BCD are congruent by the SAS postulate.
* Side AD = DC because BD is the perpendicular bisector of AC.
* Angle ADB and CDB are both right angles, and hence equal, because
BD is the perpendicular bisector of AC)
Corresponding parts of congruent triangles are equal so angle BAD = angle BCD, which was to be proven.
Regards,
MrB
Answer:
10
Step-by-step explanation:
The first thing you do is:
12 % 6 = 2
Then you have to:
2 x 5 = 10
You divide the denominator then multiply it by the Numerator
