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3 years ago

Express the surface area A (total of all six sides) of a cubical box in terms of the volume V of the box.

1 answer:

6 0

The volume of the box:
V = a³
That means : a = ∛ V
The surface area of the box:
A = 6 a² ( all 6 sides )
Answer:
A = 6 ∛ V²
$A = 6* \sqrt[3]{V^{2} }$

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kirill115 [55]

I'll assume those are squares. We know D is an identity:

$\sin^2 x + \cos ^2 x = 1$

Dividing through by $\sin ^2 x$

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That's A.

Dividing the original through by $\cos ^2 x$

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Not quite B, wrong sign on tangent.

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3 years ago

HELP ASAP PLEASE Find the area of each figure.

liraira [26]

Answer: top triangle = 10 x 4 = 40cm^2 / 2 = 20cm^2

Rectangle = 10 x 6 = 60cm^2

Right hand triangle = 6 x 4 = 24cm^2 / 2 = 12cm^2

Step-by-step explanation:

For top triangle we do 10 - 6 to get shortest side

Rectangle - ignore 14 and use top 10 cm

Finally triangle on right hand - do 14cm - 10 to get base side. Base side is 4cm.

Formula for area of triangle = b x h / 2

Note: ^2 is just to the power of 2 or squared

I hope u found this answer beneficial.

Have a nice day and Christmas holidays m8 :-)

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3 years ago

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koban [17]

Answer:

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4/16 can be divided by 4 to get 1/4

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4/10 can be divided by 2 to get 2/5

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Step-by-step explanation:

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Masteriza [31]

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Step-by-step explanation:

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USPshnik [31]

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