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yuradex [85]
3 years ago
8

Approximate the square root of 44 to the nearest tenth

Mathematics
2 answers:
exis [7]3 years ago
7 0
10x=44 x=44 so the square root of 44 is 44 im in 6th grade and i knew that wow

Artyom0805 [142]3 years ago
7 0
√44
√(4 × 11)
√4 √11
2√11
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How much 78 octane gas and 91 octane gas should be blended to make 13 gallons of 85 octane gas
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13 x 85 = 1105
78 + 91 = 169

169 / 1105 = 6.5
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What is the sixth number in the Fibonacci sequence with the first two numbers 1 and 4?
Vanyuwa [196]

Answer:

23

Step-by-step explanation:

1 + 4 = 5 so we get 1 4 5

then 4+5 = 9, 1 4 5 9

5+9 = 14, 1 4 5 9 14

9+14 = 23, so

1 4 5 9 14 23

23 is the 6th number in this sequence

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3 years ago
Will award brainliest for the correct answer!
Alex787 [66]

Answer:

<h2><em>4x³</em></h2>

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8x⁴y⁴ = 4×2×x³×x¹×y⁴ = 4x³×(2xy⁴)

12x³z² = 4×3×x³×z² = 4x³×(3z²)

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2 years ago
8 4/5 - 5 1/10 <br> Please Help
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3 years ago
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In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.
Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

m\angle O+m\angle P+m\angle Q=180^\circ        [Angle sum property]

26^\circ+m\angle P+90^\circ=180^\circ

m\angle P+116^\circ=180^\circ

m\angle P=180^\circ -116^\circ

m\angle P=64^\circ

According to Law of Sines, we get

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

Using the Law of Sines, we get

\dfrac{p}{\sin P}=\dfrac{o}{\sin O}

\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}

Substituting the given values, we get

\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}

\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}

\dfrac{4.9}{0.89879}\times 0.43837=PQ

2.38989=PQ

Approximate the value to the nearest tenth of a foot.

PQ\approx 2.4

Therefore, the length of PQ is 2.4 ft.

4 0
3 years ago
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