Answer:2. Both the populations of the Candy Kingdom and the Fire Kingdom are in decline; their populations
since 2010 are given by the functions below:
Cit) 1000 - 500
F(t) = 2500 - 1000
Will their populations ever be equal? If so, when will that happen and what will that population be?
Otherwise, briefly explain why their populations will never be equal.
Step-by-step explanation:
Answer:
The question is not explained well, Please explain it better or take a screenshot or something
Step-by-step explanation:
#5) 7.065 sq. ft.
#6) 36 ft
#7) 200.96 sq. ft.
#8) 176.625 sq. ft.
Explanation
#5) Converting 18 inches to feet, 18/12 = 1.5. The area of the circle would be given by A=3.14(1.5)² = 3.14(2.25) = 7.065 sq. ft.
#6) The radius is 18 inches, so the diameter is twice that: 18*2 = 36 inches. Converting this to feet, we have 36/12 = 3 feet. Each stone is 3 feet across. Laying 12 of them against each other would give us a total length of 12*3 = 36 feet.
#7) The radius of the entire mirror with frame is 20/2 = 10. The area of the entire mirror with frame is A=3.14(10²) = 3.14(100) = 314 in².
The area of the mirror without the frame is A=3.14(6²) = 3.14(36) = 113.04 in².
The difference between the two will give the area of the frame:
314-113.04 = 200.96 in²
#8) The area of the circular region is given by A=3.14(7.5²) = 176.625 ft²
Answer:
12 weeks
Step-by-step explanation:
Josiah and kiri are each saving money josiah starts with 100$ in savings accound and adds 5$ per week . Kiri with 40$ in her savings account adds 10$ each week after how weeks Josiah and kiri will have the same amount of money in their savings account
Josiah:
100 + 5w
Kiri:
40 + 10w
Where,
w = number of weeks
After how weeks Josiah and kiri will have the same amount of money in their savings account
Equate the savings of the both of them
100 + 5w = 40 + 10w
100 - 40 = 10w - 5w
60 = 5w
w = 60/5
= 12
w = 12 weeks
Josiah and kiri will have the same amount of money in their savings account after 12 weeks
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Answer:
100°
Step-by-step explanation:
The relevant relation for angle x is ...
x = (AB +DE)/2
and for angle y, it is ...
y =(AC -DE)/2
Using the second relation to write an expression for DE, we have ...
DE = AC -2y
In the first equation, this lets us write ...
x = (AB +(AC -2y))/2 = (AB +(2AB -2y))/2
2x = 3AB-2y . . . . . . . . . . . . . . multiply by 2
(2x +2y)/3 = AB = AC/2 . . . . . add 2y; divide by 3
AC = (4/3)(x +y) = (4/3)(60° +15°) . . . . multiply by 2, substitute known values
AC = 100°
