First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
11
Step-by-step explanation:
25% is 0.25 or 1/4
44 x 0.25 =11
Answer:
the last two
Step-by-step explanation:
You have to divide 1575 by 35 which equals 45 and then multiply that by 2 which equals 90. There are 90 foreign students
Y = -2x - 7
slope = -2 (parallel shares the same slope, -2)
Option A:
y = -2x + 7
slope = -2
At (3, 1)
y = -2(3) + 7 = 1
Answer: Option A
