<u><em>r=-199/80 is the right answer.</em></u> First, you had to multiply by 100 from both sides of the equation. And it gave us, 
. Next, you had to refine, and it gave us, 
. Then, subtract by 1470 from both sides of equation. And it gave us, 
. Simplify, and it gave us, 
. You can also divide by 320 from both sides of equation. And it gave us, 
. And finally, simplify, and it gave us the answer is <em><u>r=-199/80 is the right answer.</u></em> Hope this helps! And thank you for posting your question at here on brainly. And have a great day! -Charlie
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Could you provide more details about mixtures B and C :)?
16 7/8
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