I need help people please help me

Mathematics

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

10/4 = $\frac{10}{4}$

Step-by-step explanation:

joja [24]3 years ago

7 0

Your answer would be the 4th one : time 10%4=10/4

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There is a 10% chance of the mean oil-change time being at or below the sample mean for which there is an area of 0.10 to the

Zarrin [17]

The probability that a normally distributed data with a mean of μ and a standard deviation of σ is less than a value x is given by:

$P(X\ \textless \ x)=P\left(z\ \textless \ \frac{x-\mu}{\sigma} \right)$

Given that μ = 16.5 and σ = 0.804984 and that the probability that the <span>mean oil-change time being at or below the sample mean for which there is an area of 0.10 to the left under the normal curve, then:

$P\left(z\ \textless \ \frac{x-16.5}{0.804984} \right)=0.1\\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-16.5}{0.804984} \right)=P(z\ \textless \ -1.281) \\ \\ \Rightarrow\frac{x-16.5}{0.804984}=-1.281 \\ \\ \Rightarrow x-16.5=-1.281(0.804984)=-1.031 \\ \\ x=-1.031+16.5=15.47$ </span>