A family took a trip. they spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expen

Question

mr_godi [17]

3 years ago

15

A family took a trip. they spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expen

ses. how much did the trip cost? 366.88 440.71 514.09 587.47

Mathematics

2 answers:

Novay_Z [31] · Answer 1 · 2022-03-07T14:33:36+03:00

Novay_Z [31]3 years ago

8 0

Gasoline...........90,71
meals.............153,00
anusements...197,00
miscellaneous..73,38

total................514,09

Sladkaya [172] · Answer 2 · 2022-03-07T16:55:53+03:00

Answer: The correct option is (C) $ 514.09.

Step-by-step explanation: Given that a family took a trip, where they spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expenses.

We are to find the total cost of the trip.

The total cost of the trip will be given by the sum of all the expenses that the family done in the trip.

Therefore, the total cost of the trip is

$T_c=\$(90.71+153.00+197.00+73.38)\\\\\Rightarrow T_c=\$514.09.$

Thus, the trip cost $514.09.

Option (C) is CORRECT.