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2 years ago

9

What is the answer?!?!?!?!

2 answers:

MAXImum [283]2 years ago

8 0

The third one i think :)

quester [9]2 years ago

7 0

I be leave it is the 3rd one.

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Could someone tell me the correct answer and how to do this. Plz help meeee I'm crying because I don't know how to do this stuff

WINSTONCH [101]

Hey don't cry . I'm not good at math either but try to take a deep breath.

8 0

2 years ago

What's (2x) ^3 in expanded notation form?

inessss [21]

Answer:

<h2><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em></h2>

Step-by-step explanation:

${(2x)}^{3}$

= <em><u>2x × 2x × 2x (In expanded notation form) (Ans)</u></em>

5 0

2 years ago

Read 2 more answers

Students collected 150 cans for a food drive. there were 23 cans of corn, 48 cans of beans, and 12 cans of tomato sauce. if a st

forsale [732]

Hello!

$\bf Answer:$

The probability that the can will be either tomato sauce or beans is $\bf \frac{2}{5}$ .

___________________________________________________

$\bf Explanation:$

To find the probability of he possible outcomes, we must add them together and find the least common denominator.

$\frac{12}{150} + \frac{48}{150} = \frac{60}{150}$

Divide the numerator and the denominator by 30:

$\frac{60}{150} = \frac{2}{5}$

7 0

2 years ago

Find all points having an x coordinate of 5 whose distance from the point (2,2) is 5.

stepan [7]

Answer:

(5,6) , (5,-2)

Step-by-step explanation:

Let the required point be P(5,y).

Its distance from (2,2) is 5 units.

So, $(5-2)^{2}$ + $(y-2)^{2}$ = 25.

So, $3^{2}$ + $(y-2)^{2}$ = 25.

9 + $(y-2)^{2}$ = 25.

$(y-2)^{2}$ = 16

Two cases are possible for now

case 1 : y-2 = 4 .

y = 6

required point will be (5,6)

case 2 : y - 2 = -4.

y = -2.

required point will be (5,-2).

Two points are possible : (5,6) , (5,-2).

5 0

2 years ago

You and your friend are having a race, but since you are faster than him, you decide to give him a head start. He starts 10m in

Diano4ka-milaya [45]

Answer:

20 seconds

Step-by-step explanation:

Your friend starts 10 meters in front of the starting line.

You start from the starting line.

You run at 6 meters/ second.

Your friend runs at 5.5 meters/second.

You and your friend will be at the same distance from the starting line only when you are able to catch your friend.

The relative speed between you two is the difference in your speed and your friend's speed that is:

$6-5.5=0.5m/s$

So to cover 10 meters of separation at the speed of 0.5 meter/second it will take:

$t=\frac{10}{0.5}= \frac{100}{5}=20s$

So it will take 20 seconds for you and your friend to be at the same distance from the starting line.

8 0

2 years ago

Read 2 more answers