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mr_godi [17]
2 years ago
15

Solve nonhomogenous equation: x"+4x=cost

Mathematics
1 answer:
motikmotik2 years ago
6 0

Answer:

x(t) = Acos 2t + B sin 2t+\frac{cost}{3}

Step-by-step explanation:

Given is a non homogeneous second degree equation as

x"+4x=cost

Auxialary equation is

m^2+4 =0\\m = 2i, -2i

Hence general solution is

x = Acos 2t + B sin 2t

Particular integral is = \frac{cost}{D^2+4}

Since t has coefficient 1, we substitute

D^2 =-1\\PI = \frac{cost}{-1+4} =\frac{cost}{3}

Hence full solution is

x(t) = Acos 2t + B sin 2t+\frac{cost}{3}

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Please help I don’t understand
KIM [24]

Answer:

The equivalent ratios are:

16:10

8:5

48:30

Step-by-step explanation:

It is given that the ratios are equivalent ratios. So all the ratios will simplify to the same ratio. We can use this to find the ratios.

given ratio is:

16:10

which simplifies to

8:5

We can observe that the second ratio will be same 8:5

Now,

\frac{8}{5} = \frac{x}{30}\\x = \frac{8}{5} * 30\\x = 48

Hence,

The equivalent ratios are:

16:10

8:5

48:30

8 0
2 years ago
Rebecca went on a 240 mile trip to a soccer game. On the way back, due to road construction she had to drive 12 miles per hour s
AlladinOne [14]

Answer:

20mph

Step-by-step explanation:

because you have to divide 240 by 12 and the answer is 20

8 0
2 years ago
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storchak [24]
Set the 2x - 1 equal to 9 then work backwards. 2x - 1 = 9 Nine minus one is eight divided by two is four. X = 4
4 0
2 years ago
3. Put your straightedge along this line. Draw this line as long as you can.
GrogVix [38]

The answer is 26 trust me I will be ur friend

7 0
2 years ago
Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger
Verdich [7]

n, n + 2 - two consecutive even integers

3n = 2(n + 2) + 16     |use distributive property

3n = (2)(n) + (2)(2) + 16

3n = 2n + 4 + 16

3n = 2n + 20     |subtract 2n from both sides

n = 20

n + 2 = 20 + 2 = 22

Answer: 20, 22.

4 0
3 years ago
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