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3 years ago

Which expression is not equivalent to 6^3/6^6? 1)1/6^2 2)6^-3 3)1/216 4)1/6^3

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

Remember
(x^m)/(x^n)=x^(m-n)
and
x^(-m)=1/(x^m)
so

(6^3)/(6^3)=6^(3-6)=6^-3=1/(6^3)
first one is wrong
2nd is right
3rdone is right
4th is right

first one is wrong 1/(6^2)

andriy [413]3 years ago

6 0

I hope this helps you

A) 1/6^2=6^-2

B) 6^-3

C) 1/216=1/6^3=6^-3

D) 1/6^3=6^-3

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The rectangle is 94 m long and 58 m wide find the area use the

zepelin [54]

Answer:

Step-by-step explanation:

Area = l times w

94 x 58 = 5452

8 0

2 years ago

Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: $y=mx+b$ where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation $y=mx+b$ where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

$y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3$

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

$y=mx+b\\y=-\frac{2}{3}x+3$

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

5 0

2 years ago

Read 2 more answers

Solve the equation X³+2X²-5X -6

Natali [406]

Answer: x = {-1, -3, 2}

<u>Step-by-step explanation:</u>

x³ + 2x² - 5x - 6 = 0

Use the rational root theorem to find the possible roots: ±1, ±2, ±3, ±6

Use Long division, Synthetic division, or plug them into the equation to see which root(s) work <em>(result in a remainder of zero)</em>.

I will use Synthetic division. Let's try x = 1

1 | 1 2 -5 -6

|<u> ↓ 1 3 -2 </u>

1 3 -2 -8 ← remainder ≠ 0 so x = 1 is NOT a root

Let's try x = -1

- 1 | 1 2 -5 -6

|<u> ↓ -1 -1 6 </u>

1 1 -6 0 ← remainder = 0 so x = -1 is a root!

The coefficients of the reduced polynomial are: 1, 1, -6 --> x² + x - 6

Factor: x² + x - 6

(x + 3)(x - 2)

Set those factors equal to zero to solve for x:

x + 3 = 0 --> x = -3

x - 2 = 0 --> x = 2

Using Synthetic Division and Factoring the reduced polynomial, we found

x = -1, -3, and 2

6 0

2 years ago

Is 30/12 and 40/16 equivalent?

vlabodo [156]

$We\ pull\ the\ whole\ numbers\ from\ fractions:\\\\ \frac{30}{12}=2\frac{6}{12}=2\frac{1}{2}\\\\
\frac{40}{16}=2 \frac{8}{16}=2\frac{1}{2}\\\\\
\frac{30}{12}=\frac{40}{16}\\\\They\ are\ equivalent.$

6 0

2 years ago

The cake store is having a 30% percent off sale on all of its cakes. If the cake you want regularly costs $10, how much would yo

Akimi4 [234]

30% of £10 = £3
30% discount = £10 - £3 = £7
Cake costs £7

6 0

2 years ago