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Law Incorporation [45]
3 years ago
6

Which expression is not equivalent to 6^3/6^6? 1)1/6^2 2)6^-3 3)1/216 4)1/6^3

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0
Remember
(x^m)/(x^n)=x^(m-n)
and
x^(-m)=1/(x^m)
so

(6^3)/(6^3)=6^(3-6)=6^-3=1/(6^3)
first one is wrong
2nd is right
3rdone is right
4th is right


first one is wrong 1/(6^2)
andriy [413]3 years ago
6 0
I hope this helps you


A) 1/6^2=6^-2


B) 6^-3


C) 1/216=1/6^3=6^-3


D) 1/6^3=6^-3

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
Will give u 20 points brainlist
Vitek1552 [10]

Answer:

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Step-by-step explanation:

8 0
2 years ago
What is the volume of a rectangular prism with length 7 cm, height 8 cm, and width 15 cm? A. 840 cm3 B. 840 cm2 C. 840 cm
SVETLANKA909090 [29]
It would be A 
8*7*15=840

3 0
3 years ago
Triangle ABC has coordinates A (0, 1) B (0, 2) and C (3,2). If Triangle ABC is equivalent to triangle EDF, what is the measure o
Elanso [62]

Answer:

  3

Step-by-step explanation:

Segment BC corresponds to segment DF. The length of BC is the distance between coordinates (0, 2) and (3, 2). These points are on the same horizontal line (y=2), so the distance between them is the difference of their x-coordinates: 3 - 0 = 3.

7 0
3 years ago
Read 2 more answers
Which results only in a horizontal compression of y=1/x by a factor of 6
yan [13]

we are given

parent function as

y=\frac{1}{x}

Suppose, we are given a function y=f(x) is compressed horizontally by ''b'' units

where b>1

so, we can write as

new function as

y=f(bx)

Here, it is compressed by factor 6

so, we can replace x as 6x

and we get

y=\frac{1}{6x}

so, option-A.........Answer

7 0
3 years ago
Read 2 more answers
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