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liq [111]
3 years ago
10

Solve the equation X³+2X²-5X -6​

Mathematics
1 answer:
Natali [406]3 years ago
6 0

Answer: x = {-1, -3, 2}

<u>Step-by-step explanation:</u>

x³ + 2x² - 5x - 6 = 0

Use the rational root theorem to find the possible roots:  ±1, ±2, ±3, ±6

Use Long division, Synthetic division, or plug them into the equation to see which root(s) work <em>(result in a remainder of zero)</em>.

I will use Synthetic division.  Let's try x = 1

1 |  1    2    -5     -6

  |<u>  ↓    1      3     -2 </u>      

     1     3    -2    -8   ← remainder ≠ 0 so x = 1 is NOT a root

 Let's try x = -1

- 1 |  1     2    -5    -6

   |<u>  ↓    -1     -1     6 </u>      

      1     1     -6     0   ← remainder = 0 so x = -1 is a root!

The coefficients of the reduced polynomial are: 1, 1, -6  -->   x² + x - 6

Factor: x² + x - 6

          (x + 3)(x - 2)

Set those factors equal to zero to solve for x:

x + 3 = 0   --> x = -3

x - 2 = 0    --> x = 2

Using Synthetic Division and Factoring the reduced polynomial, we found

x = -1, -3, and 2

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dolphi86 [110]

Answer:

A) 0.265

B) 0.0265

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Step-by-step explanation:

We are given;

√7 = 2.65 and √70 = 8.37

A) √0.07 can be rewritten as;

√(7 × 1/100)

Let's deal with the digits in the bracket.

Square root of 100 is 10. Thus;

√(7 × 1/100) = (1/10)√7 = (1/10) × 2.65 = 0.265

B) √0.0007

Rewrite to get;

√(7 × 1/10000)

Square root of 1/10000 is 1/100

Thus;

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Like above;

√0.7 = √(70 × (1/100))

>> (1/10)√70 = (1/10) × 8.37 = 0.837

D) √0.007

Like above;

Rewrite to get;

√(70 × 1/10000)

Square root of 1/10000 is 1/100

Thus;

√(70 × 1/10000) = (1/100)√70 = (1/100) × 8.37 = 0.0837

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Rewritten to;

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√(1/1000000) = 1/1000

Thus; √(7 × (1/1000000)) = 1/1000 × √7 = 1/1000 × 2.65 = 0.00265

F)√0.00007

Rewritten to;

√(70 × (1/1000000))

√(1/1000000) = 1/1000

Thus; √(70 × (1/1000000)) = 1/1000 × √70 = 1/1000 × 8.37 = 0.00837

8 0
3 years ago
How do you get 7.5/8
mixas84 [53]

Answer:

0.9375

Step-by-step explanation:

Do the long division and you'll find the answer.

7 0
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3 years ago
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