I'm going to rewrite the equation assuming this is the correct form:
AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º.
1 answer:
Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
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The third side can be represented by D)
Step-by-step explanation:
Step 1:
According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.
In the given triangle, the hypotenuse is the side that is represented by z. Another side on the triangle is represented by the value y.
Step 2:
Assume the other side of the triangle measures x units.
So according to the Pythagorean theorem,
which is option D.