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fgiga [73]
3 years ago
14

Was it hard to find out?

Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0

Sorry what is hard to find out?

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You have to move the decimal place for how many space the exponent say
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Which system of linear inequalities represented by the graph y_&gt;2x-1 and y_&lt;2x+2
GREYUIT [131]
1. Check picture 1.

2. By drawing 2 pairs of points,as shown in the picture, we can easily draw the lines y=2x-1 and y=2x+2

3. We notice that the lines are parallel. (we can notice this also from the slopes of the lines, that is the coefficients of x'es, both equal to 2, which means the lines are parallel)

4. Pick (1, 3), as shown in the picture to check which side of each line we will color. (any point can work.)

5. Check (1, 3) in inequality  y_<2x+2: 
3_<2*1+2=4 is actually true, so we color the part of the line containing (1, 3) 

Check (1, 3) in the inequality y_>2x-1: 3_>2*1-1=1 which is true, so we color the part of the line containing the point:

6. So we color the part below the black line and the part above the blue line.

The solution is the part colored in both cases, which is the strip between the lines.

7. Answer: picture 2 is the graph of the system of inequalities
<span>y_>2x-1 and y_<2x+2</span>

5 0
3 years ago
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The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
defon
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
           h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

 sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
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3 years ago
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