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Hatshy [7]
3 years ago
11

A full jar of honey weighs 72/125 kg. If the weight of the empty jar is 2/9 of the weight of the full jar, what is the weight of

the empty jar?
Mathematics
2 answers:
Anit [1.1K]3 years ago
4 0
What is it??? Like& what subject ...
Bezzdna [24]3 years ago
4 0

Answer:

16/125 kg, decimal form 0.128 kg

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Write the nth term of the following sequence in terms of the first term of the sequence.
ZanzabumX [31]

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a(n) = 1 + 7(n-1)

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2. In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
scoundrel [369]

Answer:

(a) x = 30°

(b) mRS =  30°

mST =  120°

mTU  = 120°

mUR = 90°

Step-by-step explanation:

(a) In the picture attached, the diagram is shown.

Given that m arc RS = x, from the ratios:

m arc ST = 4x

m arc TU = 4x

m arc UR = 3x

The addition of the four arcs must be equal to 360°, then:

x + 4x + 4x + 3x = 360°

12x = 360°

x = 360°/12 = 30°

(b) m arc RS = x = 30°

m arc ST = 4x = 4*30° = 120°

m arc TU = 4x = 4*30° = 120°

m arc UR = 3x = 3*30° = 90°

8 0
3 years ago
What equation can represent 3 increased by a numbwr x is 9
Ksivusya [100]

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fa

Step-by-step explanation:

4 0
3 years ago
A=7/25<br> B=7/24<br> C=24/25<br> D=24/7
My name is Ann [436]

Answer:C

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3 0
3 years ago
A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

5 0
3 years ago
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