Evaluate: 2m + 5n, when m = -13 and n = 10.

Hi, can you help me answer this question, please, thank you:)

elixir [45]

EXPLANATION

We have that the area under the probability density curve is equal to 1.

As the width of the rectangle is 2, the height must be 1/2.

Then, the probability that X is between 0.2 and 1.54 is as follows:

P = 1/2 ( 1.54 - 0.2 )

= 0.67

Hence, the probability is 0.67

3 0

1 year ago

What steps can you use to solve the equation 9 equals Y +4

kirill115 [55]

Answer:

See Below

Step-by-step explanation

1) subtract 4 from both sides

You have the answer

7 0

3 years ago

PLEASE HELP ME ASAP!!!

weqwewe [10]

Answer:

D

Step-by-step explanation:

a number expressed in standard form is

a × $10^{n}$ : 1 ≤ a < 10 and n is an integer

given

(7.5 × $10^{7}$ )(2 × 10³)

= 7.5 × 2 × $10^{(7+3)}$

= 15 × $10^{10}$

= 1.5 × $10^{1}$ × $10^{10}$

= 1.5 × $10^{(1+10)}$

= 1.5 × $10^{11}$

4 0

2 years ago

What is the value of the expression 10 + (fraction 1 over 2)4 ⋅ 48?

EleoNora [17]

Equation arrangement: 10 + [1/2]^4. 48
[1/2]^4 = 1/2 * 1/2 * 1/2 * 1/2 = 1/16
10 + [1/16] * 48
According to the law of BODMAS, we have to carry out multiplication operations before we carry out addition operations, therefore, we now have.
[1/16] * 48 = 3
Then, 10 +3 =13.
Thus, the final answer is 13.

5 0

3 years ago

You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre

ra1l [238]

Answer:

1) Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

$\bar X=640$ represent the sample mean

$\sigma=150$ represent the population standard deviation

$n=40$ sample size

$\mu_o =500$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Step1:State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:

Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

Step 2: Calculate the statistic

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

We can replace in formula (1) the info given like this:

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value

Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0

3 years ago