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3 years ago

Can someone plz help me wit these three????

Mathematics

1 answer:

balandron [24]3 years ago

8 0

3. 52h
4. 8m - 5
5. Combining like terms is similar to adding and subtracting whole numbers because you just add/subtract the numbers with the same variables. It's different because in normal adding and subtracting, you can do it with any whole numbers. But with combining like terms you have to make sure that each term has the same variable or else you can't add/subtract them.

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Use the data from problem:

navik [9.2K]

Answer:

a) Sample mean: 48.71

Sample median: 48.3

Sample variance: 5.41

Sample standard deviation: 2.37

Step-by-step explanation:

a) Sample mean:

$\bar{X}=\frac{1}{N} \sum X_i=\frac{1}{80}*3896.9=48.71$

Sample median: M=48.3

Note: I order the data increasingly and take the value N / 2 = 40. In this way there are 39 values above and 39 values below the median.

Sample variance:

$s^2=\frac{1}{N-1}\sum (X_i-\bar X)^2 =(\frac{1}{80-1})*427.74=5.41$

Sample standard deviation

$s=\sqrt{s^2}=\sqrt{5.41}=2.37$

5 0

3 years ago

Solve for the value of p dont ask for ang information cuz that is literally all it says

seraphim [82]

Answer:

p = 35

Step-by-step explanation:

( 2p + 5 ) + ( 3p ) = 180

2p+5+3p=180

Combine 2p and 3p to get 5p.

5p+5=180

Subtract 5 from both sides.

5p=180−5

Subtract 5 from 180 to get 175.

5p=175

Divide both sides by 5.

p = 175\5

Divide 175 by 5 to get 35.

p = 35

5 0

3 years ago

Suppose that the statement form (p ∨ q) → (r → p) is false. What can you conclude about the truth values of the variables p, q a

ArbitrLikvidat [17]

Answer:

p is false, q is true and r is true

Step-by-step explanation:

For (p ∨ q) → (r → p) to be false, the proposition (p ∨ q) must be true and (r → p) false.

If (r → p) then r must be true and p is false, we now have truth values for these two
Now if (p v q) is true, either p, q or both must be true. Since p is false, it follows that q must be true.

6 0

3 years ago

Can u please help me in number 23 please i don’t know how to do this

pogonyaev

This is an example of systems of equations, using weird symbols rather than x or y.

We'll substitute the symbols for the variables d and c

d for diamond, c for clover.

3 + d = c

c + d = 11

We can solve for one variable in the first equation to find the true value of the other variable in the second equation.

3 + d = c

Subtract 3 from both sides.

d = c - 3

Now we have a value for d and can solve the second equation.

c + d = 11

Substitute.

c + c - 3 = 11

Add 3 to both sides.

c + c = 14

Combine like terms.

2c = 14

Divide both sides by 2.

c = 7

Now we know the absolute value of c and can solve for the value of d.

d + c = 11

d + 7 = 11

Subtract 7 from both sides.

d = 4

The diamond, or d, is equal to 4. And the clover, or c, is equal to 7. (This is your answer.)

Let me know if you have any questions.

6 0

3 years ago

Estimate the product or quotient 4/7×1/6

vlabodo [156]

Answer:4/5

hope it helps

Step-by-step explanation:

6 0

3 years ago