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PIT_PIT [208]
2 years ago
6

You and your friend get braces on the same day. You go for a checkup every fourth Tuesday. Your friend goes every third Tuesday.

After how many weeks will you both be at the dentist on the same Tuesday?
Mathematics
1 answer:
Shtirlitz [24]2 years ago
6 0

Answer: After 12 weeks they will both be at the dentists on the same Tuesday

Step-by-step explanation:

Since we have given that

He goes for a checkup every fourth Tuesday and his friend goes for a check up every third Tuesday.

We need to find the number of weeks they both will be at the dentist on the same Tuesday.

For this we will find "L.C.M. of 4 and 3 " =12

So, After 12 weeks they will both be at the dentists on the same Tuesday.

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Answer:

  1. 1/4 of a pound
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Step-by-step explanation:

For number 1:

  1. 3/4 ÷ 3 = 0.25
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For number 2:

  1. 4/5 ÷ 3 = 4/15

I hope this helps!

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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

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We know that ,

\bold{Perimeter \: of \: rectangle = 2(l + b)} \\

where <u>b </u><u>=</u><u> </u><u>width </u><u>/</u><u> </u><u>breadth</u> of rectangle

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<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>

\bold{80  = 2(25 + b)} \\  \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\  \\ \bold{\implies \: 25 + b = 40 }\\  \\ \bold{\implies \: b = 40 - 25 }\\  \\\bold{ \implies \: b = 15 \: feet}

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